Spring Security configuration

**zaidoune** · 26/03/2010, 12h17

salut ,
je travaille avec Spring security , et je trouve beaucoup de probleme

j`ai construit la page jsp : Authentification.jsp comme ca :

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<%@ taglib prefix='c' uri='http://java.sun.com/jstl/core_rt' %>
<%@ page import="org.springframework.security.ui.AbstractProcessingFilter" %>
<%@ page import="org.springframework.security.ui.webapp.AuthenticationProcessingFilter" %>
<%@ page import="org.springframework.security.AuthenticationException" %>
 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html lang="en" xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Autehentification</title>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
 
<body>
 
  <c:if test="${not empty param.login_error}">
	      <font color="red">
	        Your login attempt was not successful, try again.<br/><br/>
	        Reason: <c:out value="${SPRING_SECURITY_LAST_EXCEPTION.message}"/>.
	      </font>
	    </c:if>
 
 
    <form name="f" action="<c:url value='j_spring_security_check'/>" method="post">
	<table width="350px" align="center" style="border: 1px solid #000000; background-color: #efefef;">
	<tr>
		<td colspan=2></td>
	</tr>
	<tr>
		<td colspan=2>&nbsp;</td>
	</tr>
	Please identify yourself with a username and password:
	<tr> </tr>
	<br> </br>
	        <tr><td>User or mail:</td><td><input type='text' name='j_username' value='<c:if test="${not empty param.login_error}"><c:out value="${SPRING_SECURITY_LAST_USERNAME}"/></c:if>'/></td></tr>
	        <tr><td>Password:</td><td><input type='password' name='j_password'></td></tr>
	        <tr><td><input type="checkbox" name="_spring_security_remember_me"></td><td>Don't ask for my password for two weeks</td></tr>
 
	   	<tr>
		<td></td>
		<td><input type="submit" name="Submit" value="Login"> <input name="reset" type="reset" value="Reset"></td>
 
	</tr>
	<tr>
		<td colspan=2>&nbsp;</td>
	</tr>
	      </table>
	    </form>
 
</body>
</html>

et j`ai configuré le springseurity comme ca

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<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
	xmlns:util="http://www.springframework.org/schema/util"
	xmlns:security="http://www.springframework.org/schema/security"
	xsi:schemaLocation="http://www.springframework.org/schema/beans 
                           http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
                           http://www.springframework.org/schema/util 
                           http://www.springframework.org/schema/util/spring-util-3.0.xsd
                           http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-2.0.xsd">
<bean id="dataSource"
		class="org.springframework.jdbc.datasource.DriverManagerDataSource">
		<property name="driverClassName" value="com.mysql.jdbc.Driver" />
		<property name="url" value="jdbc:mysql://localhost:3306/proxym_data_base" />
		<property name="username" value="root" />
		<property name="password" value="" />
	</bean>
 
<security:http>
		<security:form-login login-page="/Authentification.htm" authentication-failure-url="/accessDenied.htm?login_error=true" />
		<security:intercept-url pattern="/acceuil.htm"  access="ROLE_ADMIN"/>
		<security:intercept-url pattern="/acceuil.htm" access="ROLE_ADMIN"/>
		<security:intercept-url pattern="/acceuil.htm" access="IS_AUTHENTICATED_FULLY" />
		<security:logout/>	
 
</security:http>
 
	<security:authentication-provider>
		<security:password-encoder hash="md5" >
			<security:salt-source system-wide="MySalt"/>
		</security:password-encoder>
 
		<security:jdbc-user-service data-source-ref="dataSource" authorities-by-username-query="select firstame,password from employees where firstame =?"/>
	</security:authentication-provider>
 
	<security:global-method-security secured-annotations="enabled">
		<security:protect-pointcut
			expression="execution(* com.springsource..*Service.*(..))"
			access="ROLE_USER" />
	</security:global-method-security>
 
</beans>

et pour le web.xml

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<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>GRH_LIGHT_Proxymit</display-name>
 
  <!--
		- Filtre springSecurityFilterChain
	-->
 
	<filter>
		<filter-name>springSecurityFilterChain</filter-name>
		<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
	</filter>
 
	<filter-mapping>
		<filter-name>springSecurityFilterChain</filter-name>
		<url-pattern>/*</url-pattern>
 
 
	</filter-mapping>
 
	<!--
		- ContextLoaderListener : chargement fichiers de définition de beans
	-->
	<listener>
		<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
	</listener>
 
	<!--
		- Fichiers XML de configuration, à charger par le ContextLoaderListener
	-->
	<context-param>
		<param-name>contextConfigLocation</param-name>
		<param-value>
			/WEB-INF/security-applicationContext.xml,
			/WEB-INF/dispatcher-servlet.xml
		</param-value>
	</context-param>
 
  <servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>
    <welcome-file-list>
        <welcome-file>redirect.jsp</welcome-file>
    </welcome-file-list>
</web-app>

le problème :
- si je lance mon programme il faut que je vois la page d`authentification et ce n`est pas le cas ?? donc je la lance moi même pour vérifier
-la requete sql que j`ai ecrit dans le springsecurity.xml ne marche pas pourtant j`ai fait un bean pour le data source comme deja mentionné et toujours il m`affiche un message :

Code :

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Your login attempt was not successful, try again.
 
Reason: PreparedStatementCallback; bad SQL grammar [SELECT username,password,enabled FROM users WHERE username = ?]; nested exception is com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: La table 'proxym_data_base.users' n'existe pas; nested exception is org.springframework.jdbc.BadSqlGrammarException: PreparedStatementCallback; bad SQL grammar [SELECT username,password,enabled FROM users WHERE username = ?]; nested exception is com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: La table 'proxym_data_base.users' n'existe pas

et j`ai pas une table users et je ne sais pas d`ou elle arrive parsque je n`est pas mentionné cette base dans ma requête ??

qlq 1 peut m`aider

Spring Security configuration [Security]

Spring Java

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