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C***********************************************************************
C *
C DOUBLE INTEGRAL ALGORITHM 4.5 *
C *
C***********************************************************************
C
C
C
C TO APPROXIMATE I = DOUBLE INTEGRAL (( F(X,Y) DY DX )) WITH LIMITS
C OF INTEGRATION FROM A TO B FOR X AND FROM C(X) TO D(X) FOR Y:
C
C INPUT: ENDPOINTS A,B; POSITIVE INTEGERS M, N. (ASSUME THAT THE
C ROOTS R(I,J) AND COEFFICIENTS C(I,J) ARE AVAILABLE FOR
C I EQUALS M AND N AND FOR 1<=J<=I.)
C
C OUTPUT: APPROXIMATION J TO I.
C
program double integrale
implicit none
double precision XZ,YZ,Y,A,B,H1,H2,AJ,X,C1,D1,Q,JX,K1,K2
integer M,N,J,I
real R,CO
DIMENSION R(5,5),CO(5,5)
real C,D,F
DIMENSION C(30),D(30),F(5,5)
CHARACTER*1 AA
LOGICAL OK
A=0.1
B=0.5
M=5.0
N=5.0
C CHANGE FUNCTIONS F, C, D FOR A NEW PROBLEM
C LIMITS OF INTEGRATION
C C IS THE LOWER LIMIT OF Y
C(XZ)=XZ**3
C D IS THE UPPER LIMIT OF Y
D(XZ)=XZ**2
C DEFINE INTEGRAND FUNCTION F(X,Y)
!F(XZ,YZ)=X*Y*Z
F(XZ,YZ)=EXP(YZ/XZ)
OPEN(UNIT=5,FILE='CON',ACCESS='SEQUENTIAL')
OPEN(UNIT=6,FILE='CON',ACCESS='SEQUENTIAL')
WRITE(6,*) 'This is Gaussian Quadrature for double integrals.'
WRITE(6,*) 'Have the functions F, C, and D been created?'
WRITE(6,*) 'Enter Y or N '
WRITE(6,*) ' '
READ(5,*) AA
IF(( AA .EQ. 'Y' ) .OR. ( AA .EQ. 'y' )) THEN
OK = .FALSE.
10 IF (OK) GOTO 11
WRITE(6,*) 'Input lower limit of integration and'
WRITE(6,*) 'upper limit of integration separated'
WRITE(6,*) 'by a blank.'
WRITE(6,*) ' '
READ(5,*) A, B
IF (A.GE.B) THEN
WRITE(6,*) 'lower limit must be less than upper limit'
WRITE(6,*) ' '
ELSE
OK = .TRUE.
ENDIF
GOTO 10
11 OK = .FALSE.
14 IF (OK) GOTO 15
WRITE(6,*) 'Input two positive integers M, N.'
WRITE(6,*) 'Both must be less than or equal to 5'
WRITE(6,*) 'for this implementation.'
WRITE(6,*) 'Gaussian Quadrature uses M for the outer'
WRITE(6,*) 'integral and N for the inner'
WRITE(6,*) 'integral - separate with blank.'
WRITE(6,*) ' '
READ(5,*) M,N
IF(M.LT.6.AND.N.LT.6.AND.N.GT.0.AND.M.GT.0) THEN
OK=.TRUE.
ELSE
WRITE(6,*) 'Both must be positive integers less than'
WRITE(6,*) 'or equal to 5 '
WRITE(6,*)
ENDIF
GOTO 14
15 CONTINUE
ELSE
WRITE(6,*) 'The program will end so that the functions'
WRITE(6,*) 'F, C and D can be created '
OK = .FALSE.
ENDIF
IF (.NOT.OK) GOTO 400
R(2,1) = 0.5773502692
R(2,2) = -R(2,1)
CO(2,1) = 1.0
CO(2,2) = 1.0
R(3,1) = 0.7745966692
R(3,2) = 0.0
R(3,3) = -R(3,1)
CO(3,1) = 0.5555555556
CO(3,2) = 0.8888888889
CO(3,3) = CO(3,1)
R(4,1) = 0.8611363116
R(4,2) = 0.3399810436
R(4,3) = -R(4,2)
R(4,4) = -R(4,1)
CO(4,1) = 0.3478548451
CO(4,2) = 0.6521451549
CO(4,3) = CO(4,2)
CO(4,4) = CO(4,1)
R(5,1) = 0.9061798459
R(5,2) = 0.5384693101
R(5,3) = 0.0
R(5,4) = -R(5,2)
R(5,5) = -R(5,1)
CO(5,1) = 0.2369268850
CO(5,2) = 0.4786286705
CO(5,3) = 0.5688888889
CO(5,4) = CO(5,2)
CO(5,5) = CO(5,1)
C STEP 1
H1 = ( B - A ) / 2.0
H2 = ( B + A ) / 2.0
C USE AJ INSTEAD OF J
AJ = 0.0
C STEP 2
DO 20 I = 1,M
C STEP 3
X = H1 * R(M,I) + H2
JX = 0.0
C1 = C( X )
D1 = D( X )
K1 = ( D1 - C1 ) / 2.0
K2 = ( D1 + C1 ) / 2.0
C STEP 4
DO 30 J = 1,N
Y = K1 * R(N,J) + K2
Q = F( X, Y )
JX = JX + CO(N,J) * Q
30 CONTINUE
C STEP 5
AJ = AJ + CO(M,I) * K1 * JX
20 CONTINUE
C STEP 6
AJ = AJ * H1
C STEP 7
C OUTPUT
WRITE(6,1) A,B
WRITE(6,2) AJ
WRITE(6,3) N,M
400 CLOSE(UNIT=5)
CLOSE(UNIT=6)
STOP
1 FORMAT(1X,'The double integral of F from ',E15.8,
* ' to ',E15.8,' is')
2 FORMAT(1X,E15.8)
3 FORMAT(1X,'obtained with N = ',I3,' and M = ',I3)
END |
double intégrale fortran
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