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/*
* hobdcalc
* Copyright (C) 2014 Bruggemann Eddie.
*
* This file is part of hobdcalc.
* hobdcalc is free software: you can redistribute it and/or modify
* it under the terms of the GNU General Public License as published by
* the Free Software Foundation, either version 3 of the License, or
* (at your option) any later version.
*
* hobdcalc is distributed in the hope that it will be useful,
* but WITHOUT ANY WARRANTY; without even the implied warranty of
* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
* GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License
* along with hobdcalc. If not, see <http://www.gnu.org/licenses/>
*
************************************************************************************/
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <tgmath.h>
#include <ctype.h>
#include <limits.h>
#include <inttypes.h>
#include <stdbool.h>
#include <ctype.h>
#include <errno.h>
#include <sys/time.h>
#include "conversion/utils/conversion_utils.c"
#include "conversion/int_hex/calc_int_hex.c"
#include "conversion/int_bin/calc_int_bin.c"
#include "conversion/int_oct/calc_int_oct.c"
#include "conversion/float_to_bin/float_bin.c"
#include "conversion/float_to_oct/float_oct.c"
#include "conversion/float_to_hex/float_hex.c"
#include "operations/int_result/calc_hex_int_operations.c"
#include "operations/int_result/calc_oct_int_operations.c"
#include "operations/int_result/calc_bin_int_operations.c"
#include "operations/float_result/calc_hex_float_operations.c"
#include "operations/float_result/calc_oct_float_operations.c"
#include "operations/float_result/calc_bin_float_operations.c"
/* hobdcalc can compute in the
* -) binar
* -) octal
* -) hexadecimal
* bases without problems.
*
* Arithmetics functions take the 2 operand as string
*
* whose you can get with the conversion functions who take as first argument an value
* and as second a pointer to a buffer for containing the result (size 128).
*
* The reverse functions take a string as argument and return the [integer|float] result.
*
* The limits values are for:
* integer: long long [-9223372036854775808 - 9223372036854775807].
* floats : long double 15 digits precision.
*
* You must link the type generic math file with:
* $ gcc hobdcalc.c -lm
* to compil the code.
*
* You can use the test function:
* for understanding the code.
*
* Note: I don't care about strtold() or strtoll() and the %x %o %a placeholders, only raw computing, because i made
* bad experience with it during developpment and testing.
*
* I hope this little calculator functions will be usefull for you.
* ******************************************************************************************************************/
void float_operations_test(void) ;
void integer_operations_test(void) ;
int main() {
/** integer_operations_test() ; test integer operation assertion function */
/** float_operations_test() ; test float operation assertion function */
}
void float_operations_test(void) {
long double op1,op2 ;
struct timeval tv ;
char *op1_str=malloc(128) ;
char *op2_str=malloc(128) ;
int c ;
for (c=0 ; c < 10000 ; c++) {
/** Loop for assertions for float operations */
gettimeofday(&tv,NULL) ; /** get an random seed */
srand(tv.tv_usec / 4) ; /** setting the first operand random seed */
op1= - (double) (rand() % (9223372036854775807/2)) / ((rand() % (9223372036854775807/2))+1) ; /** We take a negativ value. */
srand(tv.tv_usec / 3) ; /** setting the second operand random seed */
op2= (double) (rand() % (9223372036854775807/2)) / ((rand() % (9223372036854775807/2))+1) ; /** We take a positiv value. */
memset(op1_str,'\0',128) ;
memset(op2_str,'\0',128) ;
floattobinfloat(op1,op1_str) ; /** Convert the float op1 in an binar string op1_str */
floattobinfloat(op2,op2_str) ; /** Convert the float op2 in an binar string op2_str */
#ifdef DEBUG
/** Check if the values are correct converted */
printf("%.15Lf == %.15Lf\n",op1,binfloattofloat(op1_str)) ;
printf("%.15Lf == %.15Lf\n",op2,binfloattofloat(op2_str)) ;
#endif
if (c % 10 == 0) {
printf("iteration: %d\n",c) ;
}
if (op1 + op2 != binfloataddbinfloat(op1_str,op2_str) ) {
printf("assertion float bin add error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,binfloataddbinfloat(op1_str,op2_str)) ;
break ;
}
if (op1 - op2 != binfloatsubbinfloat(op1_str,op2_str) ) {
printf("assertion float bin sub error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,binfloataddbinfloat(op1_str,op2_str)) ;
break ;
}
if (op1 * op2 != binfloatmultbinfloat(op1_str,op2_str) ) {
printf("assertion float bin mult error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,binfloataddbinfloat(op1_str,op2_str)) ;
break ;
}
if ( (long double) op1 / (long double) op2 != binfloatdivbinfloat(op1_str,op2_str) ) {
printf("assertion float bin div error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,binfloataddbinfloat(op1_str,op2_str)) ;
break ;
}
else {
#ifdef DEBUG
/** printing all computing results. */
printf(" %s\n+ %s\n= %.15Lf\n\n %s \n- %s\n= %.15Lf\n\n %s \n* %s\n= %.15Lf\n\n %s \n/ %s\n= %.15Lf\n\n",op1_str,op2_str,binfloataddbinfloat(op1_str,op2_str),op1_str,op2_str,binfloatsubbinfloat(op1_str,op2_str),op1_str,op2_str,binfloatmultbinfloat(op1_str,op2_str),op1_str,op2_str,binfloatdivbinfloat(op1_str,op2_str)) ;
#endif
}
memset(op1_str,'\0',128) ;
memset(op2_str,'\0',128) ;
floattooctfloat(op1,op1_str) ; /** Convert the float op1 in an octal string op1_str */
floattooctfloat(op2,op2_str) ; /** Convert the float op2 in an octal string op2_str */
#ifdef DEBUG
/** Check if the values are correct converted */
printf("%.15Lf == %.15Lf\n",op1,octfloattofloat(op1_str)) ;
printf("%.15Lf == %.15Lf\n",op2,octfloattofloat(op2_str)) ;
#endif
if (op1 + op2 != octfloataddoctfloat(op1_str,op2_str) ) {
printf("assertion float oct add error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,octfloataddoctfloat(op1_str,op2_str)) ;
break ;
}
if (op1 - op2 != octfloatsuboctfloat(op1_str,op2_str) ) {
printf("assertion float oct sub error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,octfloatsuboctfloat(op1_str,op2_str)) ;
break ;
}
if (op1 * op2 != octfloatmultoctfloat(op1_str,op2_str) ) {
printf("assertion float oct mult error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,octfloatmultoctfloat(op1_str,op2_str)) ;
break ;
}
if ( (long double) op1 / (long double) op2 != octfloatdivoctfloat(op1_str,op2_str) ) {
printf("assertion float oct div error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,octfloatdivoctfloat(op1_str,op2_str)) ;
break ;
}
else {
#ifdef DEBUG
/** printing all computing results. */
printf(" %s\n+ %s\n= %.15Lf\n\n %s \n- %s\n= %.15Lf\n\n %s \n* %s\n= %.15Lf\n\n %s \n/ %s\n= %.15Lf\n\n",op1_str,op2_str,octfloataddoctfloat(op1_str,op2_str),op1_str,op2_str,octfloatsuboctfloat(op1_str,op2_str),op1_str,op2_str,octfloatmultoctfloat(op1_str,op2_str),op1_str,op2_str,octfloatdivoctfloat(op1_str,op2_str)) ;
#endif
}
memset(op1_str,'\0',128) ;
memset(op2_str,'\0',128) ;
floattohexfloat(op1,op1_str) ; /** Convert the float op1 in an hexadecimal string op1_str */
floattohexfloat(op2,op2_str) ; /** Convert the float op2 in an hexadecimal string op2_str */
op1_str[128]='\0' ;
op2_str[128]='\0' ;
#ifdef DEBUG
/** Check if the values are correct converted */
printf("%.15Lf == %.15Lf\n",op1,hexfloattofloat(op1_str)) ;
printf("%.15Lf == %.15Lf\n",op2,hexfloattofloat(op2_str)) ;
#endif
if (op1 + op2 != hexfloataddhexfloat(op1_str,op2_str) ) {
printf("assertion float hex add error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,hexfloataddhexfloat(op1_str,op2_str)) ;
break ;
}
if (op1 - op2 != hexfloatsubhexfloat(op1_str,op2_str) ) {
printf("assertion float hex sub error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,hexfloataddhexfloat(op1_str,op2_str)) ;
break ;
}
if (op1 * op2 != hexfloatmulthexfloat(op1_str,op2_str) ) {
printf("assertion float hex mult error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,hexfloataddhexfloat(op1_str,op2_str)) ;
break ;
}
if ( (long double) op1 / (long double) op2 != hexfloatdivhexfloat(op1_str,op2_str) ) {
printf("assertion float hex div error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,hexfloataddhexfloat(op1_str,op2_str)) ;
break ;
}
else {
#ifdef DEBUG
/** printing all computing results. */
printf(" %s\n+ %s\n= %.15Lf\n\n %s \n- %s\n= %.15Lf\n\n %s \n* %s\n= %.15Lf\n\n %s \n/ %s\n= %.15Lf\n\n",op1_str,op2_str,hexfloataddhexfloat(op1_str,op2_str),op1_str,op2_str,hexfloatsubhexfloat(op1_str,op2_str),op1_str,op2_str,hexfloatmulthexfloat(op1_str,op2_str),op1_str,op2_str,hexfloatdivhexfloat(op1_str,op2_str)) ;
#endif
}
}
free(op1_str) ;
free(op2_str) ;
return ;
}
void integer_operations_test(void) {
int c ;
long long op1,op2 ;
char *op1_str, *op2_str ;
op1_str=malloc(128) ;
op2_str=malloc(128) ;
struct timeval tv ;
for (c=0 ; c < 10000 ; c++) {
/** Loop for assertions for integer operations */
gettimeofday(&tv,NULL) ; /** get an random seed */
srand(tv.tv_usec /4 ) ; /** setting the first operand random seed */
op1= ((long long ) rand() % LLONG_MAX) ; /** We take a positiv value. */
srand(tv.tv_usec / 3 ) ; /** setting the second operand random seed */
op2= - ((long long) rand() % LLONG_MAX) ; /** We take a negativ value. */
memset(op1_str,'\0',128) ;
memset(op2_str,'\0',128) ;
inttobin(op1,op1_str) ; /** Convert the integer op1 in an binar string op1_str */
inttobin(op2,op2_str) ; /** Convert the integer op2 in an binar string op2_str */
#ifdef DEBUG
/** Check if the values are correct converted */
printf("%Li == %Li\n",op1,bintoint(op1_str)) ;
printf("%Li == %Li\n",op2,bintoint(op2_str)) ;
#endif
if (! (op1 + op2 == binaddbin(op1_str,op2_str) ) ) {
printf("assertion integer bin add error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,binaddbin(op1_str,op2_str)) ;
break ;
}
if (! (op1 - op2 == binsubbin(op1_str,op2_str)) ) {
printf("assertion integer bin sub error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,binsubbin(op1_str,op2_str)) ;
break ;
}
if (! (op1 * op2 == binmultbin(op1_str,op2_str)) ) {
printf("assertion integer bin mult error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,binmultbin(op1_str,op2_str)) ;
break ;
}
if (! ((long double) op1 / (long double) op2 == bindivbin(op1_str,op2_str)) ) {
printf("assertion integer bin div error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,(long double)op1+op2,bindivbin(op1_str,op2_str)) ;
break ;
}
memset(op1_str,'\0',128) ;
memset(op2_str,'\0',128) ;
inttooct(op1,op1_str) ; /** Convert the integer op1 in an octal string op1_str */
inttooct(op2,op2_str) ; /** Convert the integer op2 in an octal string op2_str */
#ifdef DEBUG
/** Check if the values are correct converted */
printf("%Li == %Li\n",op1,octtoint(op1_str)) ;
printf("%Li == %Li\n",op2,octtoint(op2_str)) ;
#endif
printf("%Li == %Li\n%Li == %Li\n",op1,octtoint(op1_str),op2,octtoint(op2_str)) ;
if (! (op1 + op2 == octaddoct(op1_str,op2_str) ) ) {
printf("assertion integer oct add error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,octaddoct(op1_str,op2_str)) ;
break ;
}
if (! (op1 - op2 == octsuboct(op1_str,op2_str)) ) {
printf("assertion integer oct sub error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,octsuboct(op1_str,op2_str)) ;
break ;
}
if (! (op1 * op2 == octmultoct(op1_str,op2_str)) ) {
printf("assertion integer oct mult error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,octmultoct(op1_str,op2_str)) ;
break ;
}
if (! ((long double) op1 / (long double) op2 == octdivoct(op1_str,op2_str)) ) {
printf("assertion integer oct div error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,(long double)op1+op2,octdivoct(op1_str,op2_str)) ;
break ;
}
memset(op1_str,'\0',128) ;
memset(op2_str,'\0',128) ;
inttohex(op1,op1_str) ; /** Convert the integer op1 in an hexadecimal string op1_str */
inttohex(op2,op2_str) ; /** Convert the integer op2 in an hexadecimal string op2_str */
#ifdef DEBUG
/** Check if the values are correct converted */
printf("%Li == %Li\n",op1,hextoint(op1_str)) ;
printf("%Li == %Li\n",op2,hextoint(op2_str)) ;
#endif
if (! (op1 + op2 == hexaddhex(op1_str,op2_str) ) ) {
printf("assertion integer hex add error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,hexaddhex(op1_str,op2_str)) ;
break ;
}
if (! (op1 - op2 == hexsubhex(op1_str,op2_str)) ) {
printf("assertion integer hex sub error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,hexsubhex(op1_str,op2_str)) ;
break ;
}
if (! (op1 * op2 == hexmulthex(op1_str,op2_str)) ) {
printf("assertion integer hex mult error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,hexmulthex(op1_str,op2_str)) ;
break ;
}
if (! ((long double) op1 / (long double) op2 == hexdivhex(op1_str,op2_str)) ) {
printf("assertion integer hex div error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,(long double)op1+op2,hexdivhex(op1_str,op2_str)) ;
break ;
}
}
free(op1_str) ;
free(op2_str) ;
return ;
} |
Conversion et calcul en base 10,2,8 et 16
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