Envoyé par Le standard (dernier draft) 5.3.1/3
A pointer to member is only formed when an explicit & is used and its operand is a qualified-id not enclosed in parentheses.
[ Note: that is, the expression &(qualified-id), where the qualified-id is enclosed in parentheses, does not form an expression of type “pointer to member.” Neither does qualified-id, because there is no implicit conversion from a qualified-id for a non-static member function to the type “pointer to member function” as there is from an lvalue of function type to the type “pointer to function” (4.3). Nor is &unqualified-id a pointer to member, even within the
scope of the unqualified-id’s class. —end note ]