[SAX] chemin complet du noeud courant

j'ai l'impression que la fonction que je demande n'éxiste pas

donc voilà ma solution

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private String path = "/";

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public void startElement (String uri, String localName, 
			String qName,Attributes attrs) throws SAXException {
 
		String eName = localName; // element name
 
		if ("".equals(eName))
			eName = qName;
 
		// construct the path 
		path = path + eName + "/";
		//System.out.println ("\t path : " + path);		
	}

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public void endElement (String uri, String localName,
			String qName) throws SAXException {
 
		String eName = localName; // element name
 
		if ("".equals(eName))
			eName = qName;
 
		//delete an element when the parser meet a end tag
		String [] splitPath = this.path.split("\\/");
		path = "/";
		for (int i=1;i<splitPath.length-1;i++) {
			path = path + splitPath[i] + "/";
		}		
	}