[XSLT] Changer l'ordre de tri

il faut faire un select par rapport à BBB puis de voir si le BBB d'après à une valeur différentes du BBB en cours de traitement
un exemple autre

Code:

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<students>
<student id="1">
	<adress>
		<street></street>
		<cp></cp>
		<city></city>
	</adress>
	<civility>
		<name>name1</name>
		<forname></forname>
		<birthday></birthday>
		<sex>M</sex>
	</civility>
	<study>
		<class></class>
	</study>
</student>
<student id="2">
	<adress>
		<street></street>
		<cp></cp>
		<city></city>
	</adress>
	<civility>
		<name>name2</name>
		<forname></forname>
		<birthday></birthday>
		<sex>M</sex>
	</civility>
	<study>
		<class></class>
	</study>
</student>
</students>

Code:

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?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 
<xsl:output 
  encoding="ISO-8859-15"
  method="html"
  doctype-public="-//W3C//DTD HTML 4.01//EN"
  doctype-system="http://www.w3.org/TR/html4/strict.dtd"
  indent="yes" />
 
<xsl:template match="students">
	<html>
	<xsl:for-each select="student">
		<xsl:sort select=".//sex" order="ascending"/>
		<xsl:variable name="sexcurrent" select=".//sex"/>
		<xsl:if test="not(preceding-sibling::student//sex=$sexcurrent)">
			<xsl:variable name="id"><xsl:value-of select=".//sex"/></xsl:variable>
			<h1> sexe: <xsl:value-of select="//base/sexs/sex[@id=$id]"/></h1>
 
			<ul>
				<xsl:for-each select="//student[.//sex=$sexcurrent]">
					<li><xsl:value-of select=".//name"/></li>
				</xsl:for-each>
			</ul>
 
		</xsl:if>
	</xsl:for-each>
 
	</html>
</xsl:template>
 
</xsl:stylesheet>