Stocker le résultat d'un InputSource

Hello,

J'ai un InputSource (org.xml.sax). Je le modifie avec XPath. Ensuite, je voudrais le stocker, c'est à dire enregistrer son contenu dans un fichier XML... Est-ce possible?

Merci, A+

P.S. Mon code:

Code:

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InputSource source; source = new InputSource(new FileInputStream(configFilePath));   // XPath creation XPathFactory fact = XPathFactory.newInstance(); XPath xpath = fact.newXPath();   //XPath evaluation XPathExpression exp; Object result; exp = xpath.compile("/configuration/logger[@name='Lua']/level/@value='DEBUG'"); result = exp.evaluate(source);   //Stocker dans configFilePath... ?!?

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Bonjour,

C'est possible comme cela :

Code:

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// Création d'un document DocumentBuilderFactory documentFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder documentBuilder = documentFactory.newDocumentBuilder(); Document document = documentBuilder.parse(configFilePath);   // XPath creation XPathFactory fact = XPathFactory.newInstance(); XPath xpath = fact.newXPath();   //XPath evaluation XPathExpression exp = xpath.compile("/configuration/logger[@name='Lua']/level/@value='DEBUG'"); Object node = exp.evaluate(document);   // Modification du node // ...   // Enregistrement TransformerFactory tFactory = TransformerFactory.newInstance(); Transformer transformer = tFactory.newTransformer(); DOMSource source = new DOMSource(document); File out = new File(configFilePath); StreamResult result = new StreamResult(out); transformer.transform(source, result);

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@peluche

jru