Quelque chose comme ça ?Citation:
Envoyé par Vesta
Code:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15 SELECT p1.userid AS user1 , p2.userid AS user2 , count(*) AS nb FROM passage AS p1 INNER JOIN passage AS p2 ON p1.userid > p2.userid AND p1.datein = p2.datein AND ABS(p1.timein - p2.timein) <= :ecart GROUP BY user1 , user2 ORDER BY nb DESC ;