Probleme position de l'image comme drawLine

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1 pièce(s) jointe(s)

Bonjour,

mon problème , que j'arrive pas avoir le même position de l'image comme Drawline ( voir angle à 90 degrés).

voir mon gif :
Pièce jointe 639119

Mon code :

Code:

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Imports System.Drawing.Drawing2D
 
Public Class Form1
 
 
    Private _Main As Image = My.Resources.Droite1
    Private Sub Form1_Paint(sender As System.Object, e As System.Windows.Forms.PaintEventArgs) Handles MyBase.Paint
        Dim g As Graphics = e.Graphics
        g.SmoothingMode = SmoothingMode.AntiAlias
        Dim rect As New Rectangle(50, 10, 500, 500)
        g.DrawEllipse(New Pen(Brushes.Black, 1), rect)
        DrawAngleImage(g, rect)
    End Sub
 
    Private Sub DrawAngleImage(g As Graphics, r As Rectangle)
        Dim center As New Point(r.Width / 1.7, r.Height / 2)
        Dim radius As Integer = center.X * 0.65
        Using Pen As New Pen(Brushes.Black, 20)
            Pen.StartCap = LineCap.RoundAnchor
            Pen.EndCap = LineCap.Flat
            g.SmoothingMode = SmoothingMode.AntiAlias
            g.DrawLine(Pen, center.X, center.Y, center.X + CInt(Math.Sin(NumericUpDown1.Value * Math.PI / 180) * radius), center.Y - CInt(Math.Cos(NumericUpDown1.Value * Math.PI / 180) * radius))
            g.DrawImage(_Main, New Rectangle(CInt(center.X - CInt(_Main.Width / 3.6)) + CInt(Math.Sin(NumericUpDown1.Value * Math.PI / 180) * radius), CInt(center.Y - CInt(_Main.Height / 2.4)) - CInt(Math.Cos(NumericUpDown1.Value * Math.PI / 180) * radius), _Main.Width, _Main.Height), 0, 0, _Main.Width, _Main.Height, GraphicsUnit.Pixel)
        End Using
    End Sub
 
    Private Sub NumericUpDown1_ValueChanged(sender As System.Object, e As System.EventArgs) Handles NumericUpDown1.ValueChanged
        Me.Refresh()
    End Sub
End Class

Pouvez-Vous m'aider à avoir la mème position comme drawline(voir angle à 90 degrés). Merci d'avance

25/05/2023, 09h44
popo

As-tu regardé du coté de RotateTransform ?

https://learn.microsoft.com/fr-fr/do...owsdesktop-8.0
25/05/2023, 21h06
Miska59

1 pièce(s) jointe(s)

Bonsoir popo, merci d'avoir répondu.

j'ai trouver la solution à mon problème . voici ce que ça donne video gif
Pièce jointe 639191
26/05/2023, 17h40
umfred

Tu pourrais aussi indiquer comment tu as résolu ton souci (à mon avis la réponse de popo t'a bien aidé)

Bonjour,

j'ai fait ceci :

Code:

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Dim newMain As Bitmap = RotateImage(_Main, NumericUpDown1.Value - 90, New Point(center.X, center.Y))
g.DrawImage(newMain, CInt(x - newMain.Width / 1.7) + CInt(Math.Sin(NumericUpDown1.Value * Math.PI / 180) * radius), CInt(y - newMain.Height / 2) - CInt(Math.Cos(NumericUpDown1.Value * Math.PI / 180) * radius), newMain.Width, newMain.Height)
 
Private Function RotateImage(ByVal bmp As Image, ByVal angle As Integer, ByVal center As Point) As Bitmap
        If bmp Is Nothing Then
            Throw New ArgumentNullException("image")
        End If
        Dim alpha As Single = angle
        While alpha < 0
            alpha += 360
        End While
        Dim gamma As Single = 90
        Dim beta As Single = 180 - angle - gamma
        Dim c1 As Single = bmp.Height
        Dim a1 As Single = Math.Abs(CSng((c1 * Math.Sin(alpha * Math.PI / 180))))
        Dim b1 As Single = Math.Abs(CSng((c1 * Math.Sin(beta * Math.PI / 180))))
        Dim c2 As Single = bmp.Width
        Dim a2 As Single = Math.Abs(CSng((c2 * Math.Sin(alpha * Math.PI / 180))))
        Dim b2 As Single = Math.Abs(CSng((c2 * Math.Sin(beta * Math.PI / 180))))
        Dim width As Integer = Convert.ToInt32(b2 + a1)
        Dim height As Integer = Convert.ToInt32(b1 + a2)
        Dim rotatedImage As New Bitmap(width, height)
        Using g As Graphics = Graphics.FromImage(rotatedImage)
            g.TranslateTransform(rotatedImage.Width / 2, rotatedImage.Height / 2)
            g.RotateTransform(angle)
            g.TranslateTransform(-rotatedImage.Width / 2, -rotatedImage.Height / 2)
            g.DrawImage(bmp, New Point((width - bmp.Width) / 2, (height - bmp.Height) / 2))
        End Using
        Return rotatedImage
    End Function

si vous avez une autre solution plus simple. je prend. cordialement

05/06/2023, 18h36
umfred

Remarque peut-être bête, mais les lignes 24 et 26 sont vraiment utiles ? sauf erreur de ma part, les 2 opérations s'annulent, non ? (quoique)