Chapitre 35. fonction next
wesh les gars,
j'ai ce code au chapitre 35 du bouquin. On me demande de decrypter le code pour revisiter ce que j'ai appris les chapitres d'avant.
J'ai pas très bien compris l'avantage de mettre "next" plutôt que de stocker directement dans une variable.
Code:
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from sys import exit
def gold_room():
print("This room is full of gold. How much do you take?")
next = input("> ")
if "0" in next or "1" in next:
how_much = int(next)
else:
dead("Man, learn to type a number.")
if how_much < 50:
print("Nice, you're not greedy, you win!")
exit(0)
else:
dead("You greedy bastard!")
def bear_room():
print("There is a bear here.")
print("The bear has a bunch of honey.")
print("The fat bear is in front of another door.")
print("How are you going to move the bear?")
bear_moved = False
while True:
next = input("> ")
if next == "take honey":
dead("The bear looks at you then slaps your face off.")
elif next == "taunt bear" and not bear_moved:
print("The bear has moved from the door. You can go through it now.")
bear_moved = True
elif next == "taunt bear" and bear_moved:
dead("The bear gets pissed off and chews your leg off.")
elif next == "open door" and bear_moved:
gold_room()
else:
print("I got no idea what that means.")
def cthulhu_room():
print("Here you see the great evil Cthulhu.")
print("He, it, whatever stares at you and you go insane.")
print("Do you flee for your life or eat your head?")
next = input("> ")
if "flee" in next:
start()
elif "head" in next:
dead("Well that was tasty!")
else:
cthulhu_room()
def dead(why):
print(why, "Good job!")
exit(0)
def start():
print("Type 'left' to take the left door. Type 'right' to take the right door.")
next = input("> ")
if next == "left":
bear_room()
elif next == "right":
cthulhu_room()
else:
dead("You stumble around the room until you starve.")
start() |
