Json, php : An error has occurred: SyntaxError: JSON.parse: unexpected character
	
	
		Bonjour,
J'essaye d'enregistrer les données d'un formulaire en json mais j'ai systématiquement l'erreur :
	Code:
	
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   |  
An error has occurred: 
[object Object] 
parsererror SyntaxError: JSON.parse: unexpected character  | 
 Mon code js :
	Code:
	
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jQuery.ajax(edit_url, {
    data: jQuery(this).serialize(),
    dataType: 'json',
    type: 'POST',
    success: function (data) {
        if (data.error === 'OK') {
            alert('ok c good')
        } else {
            alert('hi' + data.error)
        }
    },
    error: function(x,y,z){
        alert('An error has occurred:\n' + x + '\n' + y + '\n' + z);
    }
})
 
return false;
}) | 
 et mon php :
	Code:
	
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   |  
$ret = array(
    'error'             =>  'OK',
);
$update =
    "UPDATE crm_set_users SET ".
        "crm_set_users_civilite = '".mysql_real_escape_string($crm_set_users_civilite)."',".
        "crm_set_users_nom = '".mysql_real_escape_string($crm_set_users_nom)."',".
        "crm_set_users_prenom = '".mysql_real_escape_string($crm_set_users_prenom)."',".
        "crm_set_users_email = '".mysql_real_escape_string($crm_set_users_email)."', ".
        "crm_set_users_telephone = '".mysql_real_escape_string($crm_set_users_telephone)."', ".
        "crm_set_users_portable = '".mysql_real_escape_string($crm_set_users_portable)."'";
 
if($crm_set_users_photo != ""){
    $update .=", crm_set_users_photo = '".mysql_real_escape_string($crm_set_users_photo)."'";
}   
 
$update .=
    "WHERE ".
        "crm_set_users_id = '".mysql_real_escape_string($user_id)."'";
 
 
 
 
echo json_encode($ret);
exit; | 
 Lorsque j'ai ce code php uniquement, ça fonctionne :
	Code:
	
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$ret = array(
    'error'             =>  'OK',
);
echo json_encode($ret);
exit; | 
 A votre bon coeur, il me reste plus de cheveux ;)
Merci à vous