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| package org.k.developpez.forum;
import java.lang.annotation.Native;
public class Integer {
public static void main(String[] args) {
System.out.println(Integer.toHexString(234546346));
}
/**
* The number of bits used to represent an {@code int} value in two's complement binary form.
*
* @since 1.5
*/
@Native
public static final int SIZE = 32;
/**
* All possible chars for representing a number as a String
*/
final static char[] digits = { '0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a',
'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p',
'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z' };
/**
* Returns the number of zero bits preceding the highest-order ("leftmost") one-bit in the two's complement binary representation of the specified {@code int} value. Returns 32 if the specified value has no one-bits in its two's complement representation, in other words if it is equal to zero.
*
* <p>
* Note that this method is closely related to the logarithm base 2. For all positive {@code int} values x:
* <ul>
* <li>floor(log<sub>2</sub>(x)) = {@code 31 - numberOfLeadingZeros(x)}
* <li>ceil(log<sub>2</sub>(x)) = {@code 32 - numberOfLeadingZeros(x - 1)}
* </ul>
*
* @param i
* the value whose number of leading zeros is to be computed
* @return the number of zero bits preceding the highest-order ("leftmost") one-bit in the two's complement binary representation of the specified {@code int} value, or 32 if the value is equal to zero.
* @since 1.5
*/
public static int numberOfLeadingZeros(int i) {
// HD, Figure 5-6
if (i == 0)
return 32;
int n = 1;
if (i >>> 16 == 0) {
n += 16;
i <<= 16;
}
if (i >>> 24 == 0) {
n += 8;
i <<= 8;
}
if (i >>> 28 == 0) {
n += 4;
i <<= 4;
}
if (i >>> 30 == 0) {
n += 2;
i <<= 2;
}
n -= i >>> 31;
return n;
}
/**
* Returns a string representation of the integer argument as an
* unsigned integer in base 16.
*
* <p>The unsigned integer value is the argument plus 2<sup>32</sup>
* if the argument is negative; otherwise, it is equal to the
* argument. This value is converted to a string of ASCII digits
* in hexadecimal (base 16) with no extra leading
* {@code 0}s.
*
* <p>The value of the argument can be recovered from the returned
* string {@code s} by calling {@link
* Integer#parseUnsignedInt(String, int)
* Integer.parseUnsignedInt(s, 16)}.
*
* <p>If the unsigned magnitude is zero, it is represented by a
* single zero character {@code '0'} ({@code '\u005Cu0030'});
* otherwise, the first character of the representation of the
* unsigned magnitude will not be the zero character. The
* following characters are used as hexadecimal digits:
*
* <blockquote>
* {@code 0123456789abcdef}
* </blockquote>
*
* These are the characters {@code '\u005Cu0030'} through
* {@code '\u005Cu0039'} and {@code '\u005Cu0061'} through
* {@code '\u005Cu0066'}. If uppercase letters are
* desired, the {@link java.lang.String#toUpperCase()} method may
* be called on the result:
*
* <blockquote>
* {@code Integer.toHexString(n).toUpperCase()}
* </blockquote>
*
* @param i an integer to be converted to a string.
* @return the string representation of the unsigned integer value
* represented by the argument in hexadecimal (base 16).
* @see #parseUnsignedInt(String, int)
* @see #toUnsignedString(int, int)
* @since JDK1.0.2
*/
public static String toHexString(int i) {
return toUnsignedString0(i, 4);
}
/**
* Convert the integer to an unsigned number.
*/
private static String toUnsignedString0(int val, int shift) {
// assert shift > 0 && shift <=5 : "Illegal shift value";
int mag = Integer.SIZE - Integer.numberOfLeadingZeros(val);
int chars = Math.max(((mag + (shift - 1)) / shift), 1);
char[] buf = new char[chars];
formatUnsignedInt(val, shift, buf, 0, chars);
// Use special constructor which takes over "buf".
return new String(buf);
}
static int formatUnsignedInt(int val, int shift, char[] buf, int offset, int len) {
int charPos = len;
int radix = 1 << shift;
int mask = radix - 1;
do {
buf[offset + --charPos] = Integer.digits[val & mask];
val >>>= shift;
} while (val != 0 && charPos > 0);
return charPos;
}
} |
Conversion de la base 10 vers la base 16
je ne sait pas comment faire pour que 10 = A par exemple.
Répondre avec citation
ton poste tu dois marquer quand la bonne réponse tu as obtenu.
ou même G16 ?
en bas à droite du message.
Envoyé par Flodelarab
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