The C program     the func1 is called N times
given as argument

#include <time.h>
#include <stdio.h>
#include <stdlib.h>
long func1(int n){
	long  r=0;
	for (int  i=1; i<= n;i++) r+= i;
	return r;
}
int main(int argc, char* argv[]){
	clock_t c0, c1; 
	long v,count; int n;
	if ( argc < 2) {
		printf("Number of execution as argument");
		return -1;
	}
	n=atoi(argv[1]);
	c0 = clock();
	for (int j=0;j < n;j++)	v=func1(n);
	c1 = clock();
	printf ("\tCPU  time :%.2f sec", (float)(c1 - c0)/CLOCKS_PER_SEC);
	printf("\n\tThe value : %ld\n",  v);
}
----------------------------------------------------
Python3 Program  executed same number times as C

import timeit as it
import numpy as np
import sys
try :
	n=eval(sys.argv[1])
except:
	print ("Number of execution as argument");
	exit()
	
a=range(1,n+1)
b=np.array(a)
def func1():     return sum(a)
def func2():	 return np.sum(b)

print(f"sum with Python: {func1()} and NumPy {func2()} ")
tm1=it.timeit(stmt=func1, number=n)
print(f"time used Python Sum: {round(tm1,2)} sec")
tm2=it.timeit(stmt=func2, number=n)
print(f"time used  Numpy Sum: {round(tm2,2)} sec")
'''
	Example of execution
./timeC  50000
	CPU  time :7.66 sec      ---------->  Consumed by C program
	The value : 1250025000
	
python3 timeExe.py 50000
sum with Python: 1250025000 and NumPy 1250025000 
time used Python Sum: 33.0 sec  ---------->  Consumed by Python
time used  Numpy Sum: 1.13 sec  ---------->  Consumed by Numpy module

'''