Python 2.7.13 |Anaconda, Inc.| (default, Sep 21 2017, 17:38:20)

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IPython 5.4.1 -- An enhanced Interactive Python.

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In [1]: chaine = input("Entrer votre message avec input:∖n")

Entrer votre message avec input:∖n

File "<string>", line unknown

^

SyntaxError: unexpected EOF while parsing

In [2]:

In [2]: chaine = input("Entrer votre message avec input:∖n")

Entrer votre message avec input:∖n

File "<string>", line unknown

^

SyntaxError: unexpected EOF while parsing

In [3]:

In [3]: chaine = input("Entrer votre message avec input:∖n")

Entrer votre message avec input:∖nraw_

Traceback (most recent call last):

File "<ipython-input-3-ad88145539ef>", line 1, in <module>

chaine = input("Entrer votre message avec input:∖n")

File "/anaconda2/lib/python2.7/site-packages/ipykernel/ipkernel.py", line 164, in <lambda>

builtin_mod.input = lambda prompt='': eval(self.raw_input(prompt))

File "<string>", line 1, in <module>

NameError: name 'raw_' is not defined

In [4]:

In [3]:

In [3]:

In [3]:

In [3]:

In [4]: chaine = raw_input("Entrer votre message avec input:∖n")

Entrer votre message avec input:∖n

In [4]:

In [5]: "1234" = raw_input("Hello:∖2")

File "<ipython-input-5-fc35fd0f766f>", line 1

"1234" = raw_input("Hello:∖2")

SyntaxError: can't assign to literal

In [6]:

In [6]: print "vous avez entre:", 1234, type(chaine1)

vous avez entre: 1234Traceback (most recent call last):

File "<ipython-input-6-28ed234dcbf5>", line 1, in <module>

print "vous avez entre:", 1234, type(chaine1)

NameError: name 'chaine1' is not defined

In [7]:

In [7]: "1234" = raw_input("Hello input:∖2")

File "<ipython-input-7-5c20c865d0b6>", line 1

"1234" = raw_input("Hello input:∖2")

SyntaxError: can't assign to literal

In [8]:

In [8]: