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MATLAB Discussion :

Boucle à partir d'un élément d'une cellule


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MATLAB

  1. #1
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    Par défaut Boucle à partir d'un élément d'une cellule
    Bonjour,

    J'ai dans une cellule
    Code : Sélectionner tout - Visualiser dans une fenêtre à part
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"]],[14,["right",1]],[2,[" onto "]],[2,["Steintorbrücke/Steintordamm",1]]]],[2,null,null,null,[["https://maps.gstatic.com/tactile/directions/text_mode/maneuvers-2x.png",0,[16,16],[[19,630],483,0],0]]]],[["",[171,"170 m",0],[49,"49 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"]],[14,["left",1]],[2,[" onto "]],[2,["Kirchenallee",1]]]],[2,null,null,null,[["https://maps.gstatic.com/tactile/directions/text_mode/maneuvers-2x.png",0,[16,16],[[19,630],413,0],0]]]],[["",[30,"30 m",0],[16,"16 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"]],[14,["left",1]],[2,[" at "]],[2,["Bremer Reihe",1]]]],[2,null,null,null,[["https://maps.gstatic.com/tactile/directions/text_mode/maneuvers-2x.png",0,[16,16],[[19,630],413,0],0]]]]],null,0]]]]]],0,[[[["München Central Station, Bayerstraße 10A, 80335 München, Germany","0x479e75f93d8ab293:0xd5fe7137da4467b7",[null,null,48.1404584,11.5577663]],[["München Central Station","Bayerstraße 10A, 80335 München, Germany"],"München Central Station","Bayerstraße 10A, 80335 München, Germany","Bayerstraße 10A"],null,null,null,null,null,1,["München Central Station",null,null,null,null,null,null,null,null,null,null,"qKaxHD-T4wa3Z0TaN3H-1ZOyij35dZ5H"],["0x479e75f93d8ab293:0xd5fe7137da4467b7","München Central Station, Bayerstraße 10A, 80335 München, Germany",null,[null,null,48.1404584,11.5577663],0]],null,0,"BCjQKHQoSCfuAPX75dZ5HEUq6WjJDOI1HEQAAAABFK-M_EgoNbcOxHBUB5uMGKgcQoQIgAiADCjQKHQoSCdcUaL75dZ5HEVm-TX_hCQYQEQAAAMCq08g_EgoNWZixHBU_DeQGKgcQoQIgAiADCjQKHQoSCYOZg7r5dZ5HEYLdPlX1EMJkEQAAACB6X-8_EgoNIn6xHBXF5uMGKgcQoQIgAiADEMMa","Muenchen hbf"],[[["Hamburg HBF, Germany","0x47b18ee1440cd7f3:0x495c80b97a016024",[null,null,53.5528457,10.0066839]],[["Hamburg HBF","Germany"],"Hamburg HBF","Germany"],null,null,null,null,null,1,["Hamburg HBF, Germany",null,null,null,null,null,null,null,null,null,null,"CYTrHxfm9gUkYAF6uYBcSfPXDEThjrFH"],["0x47b18ee1440cd7f3:0x495c80b97a016024","Hamburg HBF, Germany",null,[null,null,53.5528457,10.0066839],0]],null,0,"BCjQKHQoSCTPM-m3hjrFHEaIafTHQVWdfEQAAACBobco_EgoNXYPrHxWbtPYFKgcQoQIgASACCjQKHQoSCQEYiTLhjrFHEdVqN3pNjcZGEQAAAODTpeo_EgoN_aHrHxWcHfcFKgcQoQIgAiADEMMa","Hamburg Hbf"]]],null,null,null,null,null,"https://www.google.com/maps/api/js?client=google-maps-lite\u0026libraries=geometry,search\u0026v=3.22.2\u0026language=en-US\u0026region=us\u0026callback=v3loaded\u0026module_domain_from_bootstrap=1","https://www.google.com/maps-lite/js/2/19a/main.js",0,"MATLAB R2014b,gzip(gfe)",null,null,0,0,0,"https://www.google.com/maps/search/Muenchen+hbf+to+Hamburg+Hbf/data=!4m2!2m1!4b1?hl=en\u0026dg=dbrw\u0026newdg=1",0,null,0,null,null,"mSkBVrDyIsnxiAa62aiABQ",null,null,["dbrw",1],null,null,null,null,0,null,null,null,[0,1,1,0,1,1,null,null,0,0,0,0,0,"",0,0],null,null,"mSkBVpv8Isuka5iSh6AH"]);       };     </script>     <meta content="IE=edge,chrome=1" http-equiv="X-UA-Compatible">     <title>Google Maps</title>     <meta name="viewport" content="initial-scale=1.0, user-scalable=no">     <meta name="referrer" content="origin">     <meta name="google" content="notranslate">     <meta property="og:title" content="Google Maps" itemprop="name">     <meta 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    je voudrais commencer une boucle à partir de l'élément," ["München Hbf",null,null,[" " , mais je ne trouve pas de moyen de dire à matlab cherche moi cet élément et ensuite prends tel élément


    existe -t - il un moyen?

    Bien à vous

    Merci d'avance

  2. #2
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    Pour être encore plus clair.
    Seul cette partie du code m'intéresse dans un premier temps. dans mon programme münchen hbf vient de route{1} , car je demande à l'utilisateur de choisir sa gare.
    donc je souhaite dire tant qu'il n'y a pas écrit ,["München Hbf",null,null,[ alors continue, quand c'est écrit, récupère ( et là ca se complique ) l'heure dans le premier cas 12:21 PM et les coordonnées 48.140232,558335 ceci jusqu'à ]],[[ mais comment faire comprendre que par exemple Nürnberg Hbf m'interesse
    Code : Sélectionner tout - Visualiser dans une fenêtre à part
    ,["München Hbf",null,null,["1442917260","Europe/Berlin","12:21 PM",7200],[null,null,48.140232,11.558335],null,"0x479e75feaa5b4f69:0x7ac27d280929b04b",null,null,null,0],["Hamburg Hbf",null,["1442937180","Europe/Berlin","5:53 PM",7200],null,[null,null,53.552736,10.006909],null,"0x47b18ee1440cd7f3:0x495c80b97a016024",null,null,null,0],[["Ingolstadt Hbf",null,["1442919480","Europe/Berlin","12:58 PM",7200],["1442919660","Europe/Berlin","1:01 PM",7200],[null,null,48.744541,11.437337],null,"0x479eff1abc9d9261:0x1c002074ea972890",null,null,null,0],["Nürnberg Hbf",null,["1442921400","Europe/Berlin","1:30 PM",7200],["1442921580","Europe/Berlin","1:33 PM",7200],[null,null,49.445616,11.082989],null,"0x479f570a6dbc229d:0xd8a18c567aeb573b",null,null,null,0],["Würzburg Hbf",null,["1442924820","Europe/Berlin","2:27 PM",7200],["1442925000","Europe/Berlin","2:30 PM",7200],[null,null,49.801796,9.935779999999999],null,"0x47a291cdb445a77f:0x6648770af49969a4",null,null,null,0],["Fulda",null,["1442926920","Europe/Berlin","3:02 PM",7200],["1442927040","Europe/Berlin","3:04 PM",7200],[null,null,50.554723,9.683976999999999],null,"0x47a3369b09de9c6f:0x88c508c127032d96",null,null,null,0],["Kassel-Wilhelmshöhe",null,["1442928840","Europe/Berlin","3:34 PM",7200],["1442928960","Europe/Berlin","3:36 PM",7200],[null,null,51.313114,9.446897999999999],null,"0x47bb3f70a688ca97:0x97580dab1c8b63e",null,null,null,0],["Göttingen",null,["1442930040","Europe/Berlin","3:54 PM",7200],["1442930160","Europe/Berlin","3:56 PM",7200],[null,null,51.536815,9.926072],null,"0x47a4d4b816072201:0x76844cee4150c6d7",null,null,null,0],["Hannover Hbf",null,["1442932320","Europe/Berlin","4:32 PM",7200],["1442932560","Europe/Berlin","4:36 PM",7200],[null,null,52.37676099999999,9.741021],null,"0x47b074ae346d4a51:0xc1d62d43907c0502",null,null,null,0],["Hamburg-Harburg",null,["1442936520","Europe/Berlin","5:42 PM",7200],["1442936640","Europe/Berlin","5:44 PM",7200],[null,null,53.455908,9.991700999999999],null,"0x47b191a2490c7c1f:0xfcc05587e0a213a3",null,null,null,0]]],null,null,null,[[[2614.437786204986,11.558335,48.140232],[0,0,0],[1024,768],13.10000038146973],[[null,null,48.14028521746894,11.55839323487485],[null,null,48.140232,11.558335]],[

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    Bonjour,

    Je m'interroge dans un premier temps sur la classe des éléments de ton tableau de cellules. ça n'a pas l'air d'être des strings?
    Si vous cherchez des réponses sur ce forum il faudra avant tout expliquer clairement votre problème et exposer la démarche que vous avez entreprise pour le résoudre. Fournissez une base de travail et de réflexion à vos interlocuteurs!

  4. #4
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    en fait j'ai obtenu ce gros fichier du code source de google maps et je l'ai mis dans une cellule
    Code : Sélectionner tout - Visualiser dans une fenêtre à part
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    infoA = cell(1,1);
    infoA{1,1}=info;
    info = le code source et infoA le tableau dans lequel j'ai mis dans la premiere cellule tout ce charabia

  5. #5
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    Et que te renvoie la commande whos info ?
    Si vous cherchez des réponses sur ce forum il faudra avant tout expliquer clairement votre problème et exposer la démarche que vous avez entreprise pour le résoudre. Fournissez une base de travail et de réflexion à vos interlocuteurs!

  6. #6
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    Name Size Bytes Class Attributes

    info 1x55842 111684 char

  7. #7
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    Ok donc c'est bien une chaîne de caractère alors.

    Tu peux donc commencer par t'intéresser aux fonctions de comparaisons de chaînes de caractères comme strfind ou strcmp par exemple.

    Exemple:
    Code : Sélectionner tout - Visualiser dans une fenêtre à part
    idx = strfind('["München Hbf",null,null,["',infoA{1,1})
    Si vous cherchez des réponses sur ce forum il faudra avant tout expliquer clairement votre problème et exposer la démarche que vous avez entreprise pour le résoudre. Fournissez une base de travail et de réflexion à vos interlocuteurs!

  8. #8
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    ça me met
    idx =

    []

  9. #9
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    Ca devrait en renvoyer quelque chose non ?
    ou à partir de cette ligne, je peux écrire une boucle?

  10. #10
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    Je ne comprends pas trop ce que tu désires faire avec la boucle. Mais en effet ça devrait te renvoyer quelques choses. Essaie avec un truc plus simple pour voir

    Code : Sélectionner tout - Visualiser dans une fenêtre à part
    idx = strfind('München',infoA{1,1})
    Si vous cherchez des réponses sur ce forum il faudra avant tout expliquer clairement votre problème et exposer la démarche que vous avez entreprise pour le résoudre. Fournissez une base de travail et de réflexion à vos interlocuteurs!

  11. #11
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    les arguments de ton strfind sont inversées. Du coup normal ça te donne rien.

    findstr(phrase_longue,phrase_courte);

  12. #12
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    Code : Sélectionner tout - Visualiser dans une fenêtre à part
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    idx =
     
            3278        4725        8169        9605
    ca me renvoie donc ca.
    si je veux dire le premier donc 3278
    Code : Sélectionner tout - Visualiser dans une fenêtre à part
    ,["München Hbf",null,null,["1442917260","Europe/Berlin","12:21 PM",7200],[null,null,48.140232,11.558335],null,"0x479e75feaa5b4f69:0x7ac27d280929b04b",null,null,null,0],["Hamburg Hbf",null,["1442937180","Europe/Berlin","5:53 PM",7200],null,[null,null,53.552736,10.006909],null,"0x47b18ee1440cd7f3:0x495c80b97a016024",null,null,null,0],[["Ingolstadt Hbf",null,["1442919480","Europe/Berlin","12:58
    Dans ce bout de code source il y a donc le München Hbf (en caractère 3278)
    je souhaite obtenir en sortir un tableau du genre münchen Hbf 12h21 PM 48.140232,11.558335 (les coordonnées)
    ensuite obtenir Hamburg Hbf 5:53 PM et les coordonnées egalement
    et la meme chose pour Ingolstadt etc

    en gros là j'ai mon idx 3278 quand j'ai '["München Hbf",null,null' alors prendre les éléments devant PM puis les elements après ,[null,null, jusqu'au crochet. Au prochain null,null,null,0] prendre l'élément suivant (ici donc Hamburg ) etc
    c'est plus clair?

  13. #13
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    La c'est du traitement de données standard, tu peux t'en sortir avec quelques boucles et des fonctions comme strfind ou strsplit.

  14. #14
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    Merci,

    Je maitrise pas trop trop matlab mais dejà comment je peux faire pour dire München Hbf va dans la première case d'un tableau?
    idx = findstr('["München Hbf",null,null',infoA{1,1})
    tableau{1,1} = idx ca va écrire '["München Hbf",null,null' et non pas seulement la gare.
    3278 c'est le caractère " ou la fin ?

  15. #15
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    j'ai ceci
    idx = findstr('["München Hbf",null,null',infoA{1,1})
    idx1 =findstr(']],[',infoA{1,1})

    je souhaite dire garde que ce qui est entre le premier idx trouvé jusqu'au idx1>idx

    res = Vect(idx:idx1>idx);

    je veux du premier idx au idx1 supérieur au premier idx

  16. #16
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    Citation Envoyé par petchi Voir le message
    les arguments de ton strfind sont inversées. Du coup normal ça te donne rien.

    findstr(phrase_longue,phrase_courte);
    Oups mea culpa pour cette erreur! J'avais en effet inversé les arguments.

    Citation Envoyé par mimieloic
    j'ai ceci
    idx = findstr('["München Hbf",null,null',infoA{1,1})
    idx1 =findstr(']],[',infoA{1,1})

    je souhaite dire garde que ce qui est entre le premier idx trouvé jusqu'au idx1>idx

    res = Vect(idx:idx1>idx);

    je veux du premier idx au idx1 supérieur au premier idx
    Et donc où est la question/le problème?
    Si vous cherchez des réponses sur ce forum il faudra avant tout expliquer clairement votre problème et exposer la démarche que vous avez entreprise pour le résoudre. Fournissez une base de travail et de réflexion à vos interlocuteurs!

  17. #17
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    idx = findstr('["München Hbf",null,null',infoA{1,1})

    Code : Sélectionner tout - Visualiser dans une fenêtre à part
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    idx1 =findstr(']],[',infoA{1,1})
     
    idx =
     
            3289        4738        8183        9627
     
    idx1 =
     
      Columns 1 through 10
     
            1440        1752        2694        2710        2948        4425        4682        4698        5847        5863
    etc etc
    après analyse de mon fichier les données qui m'interessent se trouvent entre 3289 (premiere fois que idx rencontre '["München Hbf",null,null' et la valeur de idx1 supérieur à celle de la premiere valeur de idx donc ici 4425.
    mais je vois pas comment faire
    donc en gros je veux garder ce qu'il y a entre 3289 et 4425. mais sans ecrire 3289 et 4425 car ca change à chaque fois

  18. #18
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    ich habe geschafft! j'ai reussi
    Code : Sélectionner tout - Visualiser dans une fenêtre à part
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    idx(1)
     
    idx1 =findstr(']]]',info)
    n = 1;
    while idx1(n)<idx(1)
        n=n+1;
    end
    %%
    Q = info(idx(1):idx1(n))

  19. #19
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    Citation Envoyé par Gooby Voir le message
    Oups mea culpa pour cette erreur! J'avais en effet inversé les arguments.
    C'est le genre de petite erreur que je fais aussi tout le temps .

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