Discussion :

[Luke spywoker]

Salut les C,

Je vous mets a disposition ma dernière humble création: hobdcalc.

IL s'agit d'un ensemble de fonctions permettant:

-) La Conversion:

-) convertir depuis l'entier vers les base 2, 8 et 16. Le résultat est un string représentant la valeur (maximal signed long long) sous forme:
-> binaire.
-> octale.
-> hexadécimale.

-) Convertir depuis un float vers les base 2, 8 et 16. Le résultat est un string représentant la valeur (maximal signed long double, précision maximale double (%.15Lf) ) sous forme:
-> binaire.
-> octale.
-> hexadécimale.

-) Le calcul direct d'entiers (arguments donner sous formes de strings (binaire, octal ou hexadécimale).
-) Addition.
-) Soustraction.
-) Multiplications.
-) Division.
Le résultat étant de type long long sauf pour la division (long double).

-) Le calcul direct de float (arguments donner sous formes de strings (binaire, octal ou hexadécimale).
-) Addition.
-) Soustraction.
-) Multiplications.
-) Division.
Le résultat étant de type long double.

Le fichiers hobdcalc.c contient une fonction main() et des fonctions de test vous permettant de vous familiariser avec les fonctions et de comprendre comment les utiliser.

Pour vous mettre l'eau a la bouche voici le contenus du fichiers hobdcalc.c
(vous remarquerez grâce aux include, la hiérarchisation de l'archive avec un dossier-fichier a chaque effet).

Code :

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/*
 * hobdcalc 
 * Copyright (C) 2014 Bruggemann Eddie.
 * 
 * This file is part of hobdcalc.
 * hobdcalc is free software: you can redistribute it and/or modify
 * it under the terms of the GNU General Public License as published by
 * the Free Software Foundation, either version 3 of the License, or
 * (at your option) any later version.
 *
 * hobdcalc is distributed in the hope that it will be useful,
 * but WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
 * GNU General Public License for more details.
 *
 * You should have received a copy of the GNU General Public License
 * along with hobdcalc. If not, see <http://www.gnu.org/licenses/>
 * 
 ************************************************************************************/
 
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <tgmath.h>
#include <ctype.h>
#include <limits.h>
#include <inttypes.h>
#include <stdbool.h>
#include <ctype.h>
#include <errno.h>
#include <sys/time.h>
 
#include "conversion/utils/conversion_utils.c"
 
#include "conversion/int_hex/calc_int_hex.c"
#include "conversion/int_bin/calc_int_bin.c"
#include "conversion/int_oct/calc_int_oct.c" 
 
 
#include "conversion/float_to_bin/float_bin.c"
#include "conversion/float_to_oct/float_oct.c"
#include "conversion/float_to_hex/float_hex.c"
 
#include "operations/int_result/calc_hex_int_operations.c"
#include "operations/int_result/calc_oct_int_operations.c"
#include "operations/int_result/calc_bin_int_operations.c"
 
#include "operations/float_result/calc_hex_float_operations.c"
#include "operations/float_result/calc_oct_float_operations.c"
#include "operations/float_result/calc_bin_float_operations.c"
 
 
/* hobdcalc can compute in the 
 * -) binar
 * -) octal
 * -) hexadecimal
 * bases without problems.
 * 
 * Arithmetics functions take the 2 operand as string
 * 
 * whose you can get with the conversion functions who take as first argument an value 
 * and as second a pointer to a buffer for containing the result (size 128).
 * 
 * The reverse functions take a string as argument and return the [integer|float] result.
 * 
 * The limits values are for:
 * integer: long long [-9223372036854775808 - 9223372036854775807].
 * floats : long double 15 digits precision.
 * 
 * You must link the type generic math file with:
 * $ gcc hobdcalc.c -lm
 * to compil the code.
 * 
 * You can use the test function:
 * for understanding the code. 
 * 
 * Note: I don't care about strtold() or strtoll() and the %x %o %a placeholders, only raw computing, because i made
 *       bad experience with it during developpment and testing.
 * 
 *       I hope this little calculator functions will be usefull for you.     
 * ******************************************************************************************************************/
 
void float_operations_test(void) ;
 
void integer_operations_test(void) ;
 
int main() {
 
  /** integer_operations_test() ; test integer operation assertion function */
  /** float_operations_test()   ; test float operation assertion function */
 
}
 
void float_operations_test(void) {
  long double op1,op2 ;
  struct timeval tv ;
  char *op1_str=malloc(128) ;
  char *op2_str=malloc(128) ;
  int c ;
 
  for (c=0 ; c < 10000 ; c++) {
    /** Loop for assertions for float operations */
    gettimeofday(&tv,NULL) ;   /** get an random seed */
 
    srand(tv.tv_usec / 4) ;    /** setting the first operand random seed */
    op1= - (double) (rand() % (9223372036854775807/2)) / ((rand() % (9223372036854775807/2))+1) ; /** We take a negativ value. */
 
    srand(tv.tv_usec / 3) ;   /** setting the second operand random seed */
    op2= (double) (rand() % (9223372036854775807/2)) / ((rand() % (9223372036854775807/2))+1) ;   /** We take a positiv value. */
 
 
    memset(op1_str,'\0',128) ;
    memset(op2_str,'\0',128) ;
 
    floattobinfloat(op1,op1_str) ; /** Convert the float op1 in an binar string op1_str */
    floattobinfloat(op2,op2_str) ; /** Convert the float op2 in an binar string op2_str */
 
 
 
    #ifdef DEBUG
    /** Check if the values are correct converted */
    printf("%.15Lf == %.15Lf\n",op1,binfloattofloat(op1_str)) ;
    printf("%.15Lf == %.15Lf\n",op2,binfloattofloat(op2_str)) ;
    #endif
 
    if (c % 10 == 0) {
      printf("iteration: %d\n",c) ;
    }
    if (op1 + op2 != binfloataddbinfloat(op1_str,op2_str) ) {
      printf("assertion float bin add error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,binfloataddbinfloat(op1_str,op2_str)) ;
      break ;
    }
    if (op1 - op2 != binfloatsubbinfloat(op1_str,op2_str) ) {
      printf("assertion float bin sub error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,binfloataddbinfloat(op1_str,op2_str)) ;
      break ;
    }
    if (op1 * op2 != binfloatmultbinfloat(op1_str,op2_str) ) {
      printf("assertion float bin mult error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,binfloataddbinfloat(op1_str,op2_str)) ;
      break ;
    }
    if ( (long double) op1 / (long double) op2 != binfloatdivbinfloat(op1_str,op2_str) ) {
      printf("assertion float bin div error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,binfloataddbinfloat(op1_str,op2_str)) ;
      break ;
    }
    else {
      #ifdef DEBUG
      /** printing all computing results. */
      printf("  %s\n+ %s\n= %.15Lf\n\n  %s \n- %s\n= %.15Lf\n\n  %s \n* %s\n= %.15Lf\n\n  %s \n/ %s\n= %.15Lf\n\n",op1_str,op2_str,binfloataddbinfloat(op1_str,op2_str),op1_str,op2_str,binfloatsubbinfloat(op1_str,op2_str),op1_str,op2_str,binfloatmultbinfloat(op1_str,op2_str),op1_str,op2_str,binfloatdivbinfloat(op1_str,op2_str)) ;
      #endif 
    }
    memset(op1_str,'\0',128) ;
    memset(op2_str,'\0',128) ;
    floattooctfloat(op1,op1_str) ; /** Convert the float op1 in an octal string op1_str */
    floattooctfloat(op2,op2_str) ; /** Convert the float op2 in an octal string op2_str */
 
    #ifdef DEBUG
    /** Check if the values are correct converted */
    printf("%.15Lf == %.15Lf\n",op1,octfloattofloat(op1_str)) ;
    printf("%.15Lf == %.15Lf\n",op2,octfloattofloat(op2_str)) ;
    #endif
 
    if (op1 + op2 != octfloataddoctfloat(op1_str,op2_str) ) {
      printf("assertion float oct add error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,octfloataddoctfloat(op1_str,op2_str)) ;
      break ;
    }
    if (op1 - op2 != octfloatsuboctfloat(op1_str,op2_str) ) {
      printf("assertion float oct sub error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,octfloatsuboctfloat(op1_str,op2_str)) ;
      break ;
    }
    if (op1 * op2 != octfloatmultoctfloat(op1_str,op2_str) ) {
      printf("assertion float oct mult error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,octfloatmultoctfloat(op1_str,op2_str)) ;
      break ;
    }
    if ( (long double) op1 / (long double) op2 != octfloatdivoctfloat(op1_str,op2_str) ) {
      printf("assertion float oct div error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,octfloatdivoctfloat(op1_str,op2_str)) ;
      break ;
    }
    else {
      #ifdef DEBUG
      /** printing all computing results. */
      printf("  %s\n+ %s\n= %.15Lf\n\n  %s \n- %s\n= %.15Lf\n\n  %s \n* %s\n= %.15Lf\n\n  %s \n/ %s\n= %.15Lf\n\n",op1_str,op2_str,octfloataddoctfloat(op1_str,op2_str),op1_str,op2_str,octfloatsuboctfloat(op1_str,op2_str),op1_str,op2_str,octfloatmultoctfloat(op1_str,op2_str),op1_str,op2_str,octfloatdivoctfloat(op1_str,op2_str)) ;
      #endif 
    }
 
 
    memset(op1_str,'\0',128) ;
    memset(op2_str,'\0',128) ;
    floattohexfloat(op1,op1_str) ; /** Convert the float op1 in an hexadecimal string op1_str */
    floattohexfloat(op2,op2_str) ; /** Convert the float op2 in an hexadecimal string op2_str */
    op1_str[128]='\0' ;
    op2_str[128]='\0' ;
 
 
    #ifdef DEBUG
    /** Check if the values are correct converted */
    printf("%.15Lf == %.15Lf\n",op1,hexfloattofloat(op1_str)) ;
    printf("%.15Lf == %.15Lf\n",op2,hexfloattofloat(op2_str)) ;
    #endif
 
    if (op1 + op2 != hexfloataddhexfloat(op1_str,op2_str) ) {
      printf("assertion float hex add error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,hexfloataddhexfloat(op1_str,op2_str)) ;
      break ;
    }
 
    if (op1 - op2 != hexfloatsubhexfloat(op1_str,op2_str) ) {
      printf("assertion float hex sub error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,hexfloataddhexfloat(op1_str,op2_str)) ;
      break ;
    }
 
    if (op1 * op2 != hexfloatmulthexfloat(op1_str,op2_str) ) {
      printf("assertion float hex mult error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,hexfloataddhexfloat(op1_str,op2_str)) ;
      break ;
    }
    if ( (long double) op1 / (long double) op2 != hexfloatdivhexfloat(op1_str,op2_str) ) {
      printf("assertion float hex div error by iteration %d:\nop1: %.15Lf == %s\nop2: %.15Lf == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,op1+op2,hexfloataddhexfloat(op1_str,op2_str)) ;
      break ;
    }
    else {
      #ifdef DEBUG
      /** printing all computing results. */
      printf("  %s\n+ %s\n= %.15Lf\n\n  %s \n- %s\n= %.15Lf\n\n  %s \n* %s\n= %.15Lf\n\n  %s \n/ %s\n= %.15Lf\n\n",op1_str,op2_str,hexfloataddhexfloat(op1_str,op2_str),op1_str,op2_str,hexfloatsubhexfloat(op1_str,op2_str),op1_str,op2_str,hexfloatmulthexfloat(op1_str,op2_str),op1_str,op2_str,hexfloatdivhexfloat(op1_str,op2_str)) ;
      #endif 
    }
 
 
 
  }
  free(op1_str) ;
  free(op2_str) ;
 
  return  ;
}
 
void integer_operations_test(void) {
  int c ;
  long long op1,op2 ;
  char *op1_str, *op2_str ;
  op1_str=malloc(128) ;
 
  op2_str=malloc(128) ;
 
  struct timeval tv ;
 
  for (c=0 ; c < 10000 ; c++) {
    /** Loop for assertions for integer operations */
    gettimeofday(&tv,NULL) ;   /** get an random seed */
 
    srand(tv.tv_usec /4 ) ;    /** setting the first operand random seed */
    op1= ((long long ) rand() % LLONG_MAX) ; /** We take a positiv value. */
 
    srand(tv.tv_usec / 3 ) ;   /** setting the second operand random seed */
    op2=  -  ((long long) rand() % LLONG_MAX) ; /** We take a negativ value. */
 
    memset(op1_str,'\0',128) ;
    memset(op2_str,'\0',128) ;
    inttobin(op1,op1_str) ; /** Convert the integer op1 in an binar string op1_str */
    inttobin(op2,op2_str) ; /** Convert the integer op2 in an binar string op2_str */
 
    #ifdef DEBUG
    /** Check if the values are correct converted */
    printf("%Li == %Li\n",op1,bintoint(op1_str)) ; 
    printf("%Li == %Li\n",op2,bintoint(op2_str)) ; 
    #endif
 
    if (! (op1 + op2 == binaddbin(op1_str,op2_str) ) ) {
      printf("assertion integer bin add error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,binaddbin(op1_str,op2_str)) ;
      break ;
    }
    if (! (op1 - op2 == binsubbin(op1_str,op2_str)) ) {
      printf("assertion integer bin sub error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,binsubbin(op1_str,op2_str)) ;
      break ;
    }
    if (! (op1 * op2 == binmultbin(op1_str,op2_str)) ) { 
      printf("assertion integer bin mult error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,binmultbin(op1_str,op2_str)) ;
      break ;
    }
    if (! ((long double) op1 / (long double) op2 == bindivbin(op1_str,op2_str)) ) {
      printf("assertion integer bin div error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,(long double)op1+op2,bindivbin(op1_str,op2_str)) ;
      break ;
    }
 
 
 
    memset(op1_str,'\0',128) ;
    memset(op2_str,'\0',128) ;
    inttooct(op1,op1_str) ; /** Convert the integer op1 in an octal string op1_str */ 
    inttooct(op2,op2_str) ; /** Convert the integer op2 in an octal string op2_str */
 
    #ifdef DEBUG
    /** Check if the values are correct converted */
    printf("%Li == %Li\n",op1,octtoint(op1_str)) ;
    printf("%Li == %Li\n",op2,octtoint(op2_str)) ;
    #endif
 
    printf("%Li == %Li\n%Li == %Li\n",op1,octtoint(op1_str),op2,octtoint(op2_str)) ;
 
    if (! (op1 + op2 == octaddoct(op1_str,op2_str) ) ) {
	printf("assertion integer oct add error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,octaddoct(op1_str,op2_str)) ;
	break ;
      }
    if (! (op1 - op2 == octsuboct(op1_str,op2_str)) ) {
      printf("assertion integer oct sub error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,octsuboct(op1_str,op2_str)) ;
      break ;
    }
    if (! (op1 * op2 == octmultoct(op1_str,op2_str)) ) { 
      printf("assertion integer oct mult error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,octmultoct(op1_str,op2_str)) ;
      break ;
    }
    if (! ((long double) op1 / (long double) op2 == octdivoct(op1_str,op2_str)) ) {
      printf("assertion integer oct div error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,(long double)op1+op2,octdivoct(op1_str,op2_str)) ;
      break ;
    }
 
 
 
    memset(op1_str,'\0',128) ;
    memset(op2_str,'\0',128) ; 
    inttohex(op1,op1_str) ; /** Convert the integer op1 in an hexadecimal string op1_str */
    inttohex(op2,op2_str) ; /** Convert the integer op2 in an hexadecimal string op2_str */
 
    #ifdef DEBUG
    /** Check if the values are correct converted */
    printf("%Li == %Li\n",op1,hextoint(op1_str)) ;
    printf("%Li == %Li\n",op2,hextoint(op2_str)) ;
    #endif
 
    if (! (op1 + op2 == hexaddhex(op1_str,op2_str) ) ) {
	printf("assertion integer hex add error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,hexaddhex(op1_str,op2_str)) ;
	break ;
    }
    if (! (op1 - op2 == hexsubhex(op1_str,op2_str)) ) {
      printf("assertion integer hex sub error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,hexsubhex(op1_str,op2_str)) ;
      break ;
    }
    if (! (op1 * op2 == hexmulthex(op1_str,op2_str)) ) { 
      printf("assertion integer hex mult error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %Li\nerror: %Li\n",c,op1,op1_str,op2,op2_str,op1+op2,hexmulthex(op1_str,op2_str)) ;
      break ;
    }
    if (! ((long double) op1 / (long double) op2 == hexdivhex(op1_str,op2_str)) ) {
      printf("assertion integer hex div error by iteration %d:\nop1: %Li == %s\nop2: %Li == %s\nresult: %.15Lf\nerror: %.15Lf\n",c,op1,op1_str,op2,op2_str,(long double)op1+op2,hexdivhex(op1_str,op2_str)) ;
      break ;
    }
 
 
 
  }
 
  free(op1_str) ;
  free(op2_str) ;
  return ;
 
}

Merci pour vos commentaires en espérant que ça vous soit utile.
Désolé pour la limitation a 8 bytes je n'ai pus faire mieux.

[Bktero]

(vous remarquerez grâce aux include, la hiérarchisation de l'archive avec un dossier-fichier a chaque effet

Inclusions de .c, c'est gentil de le faire remarquer

Pourrais-tu attacher l'archive tar à un message ici plutôt que de donner un lien vers un site qui fait peur ?

[Luke spywoker]

Pour ceux a qui mon index fait peur,
et suite a la réclamation de Bktero dont je ne comprend pas les motivations,
mais dont le souhait je respecte:

téléchargez hobdcalc: un ensemble de fonctions de conversion et de calcul en base 12, 8, 2, et 10 ici.