Je reçois l'erreur suivante :
Parse error: parse error in c:\program files (x86)\easyphp1-8\www\nouveau dossier\test.php on line 38
Voici mon code PHP :
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| <?php
require 'FastJSON.class.php';
$hote = 'local';
$base = 'androidhive';
$user = '';
$pass = '';
$db = mssql_connect ('HPWALID', '', '');
$ret = mssql_select_db ('androidhive', $db) or die ('Echec lors de la connexion: '.mysql_error ());
$result = mssql_query("SELECT * FROM TabStock");
if (mssql_num_rows($result) > 0) {
// looping through all results
// products node
$response["products"] = array();
while ($row = mssql_fetch_array($result)) {
// temp user array
$product = array();
$product["CodArt"] = $row["CodArt"];
// push single product into final response array
array_push($response["products"], $product);
}
// success
$response["success"] = 1;
// echoing JSON response
echo json_encode($response);
} else {
// no products found
$response["success"] = 0;
$response["message"] = "No products found";
// echo no users JSON
// echo json_encode($response);
$var = FastJSON:encode($respnse);
echo $var;
}
?> |
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