bonjour à tous,
j'ai un énorme problème, comme tout le monde ici...
je travail sur kettle qui me permet d’insérer une étape faisant appel à un script java que voici :
Code :
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| //CREATE a Locale according TO the specified LANGUAGE code
var locale = new java.util.Locale(
language_code
, country_code
);
//CREATE a calendar, USE the specified initial date
var calendar = new java.util.GregorianCalendar(locale);
calendar.setTime(initial_date);
//SET the calendar TO the current date BY adding DaySequence days
//calendar.ADD(calendar.DAY_OF_MONTH,DaySequence - 1); anciene ligne
calendar.ADD(calendar.HOUR_OF_DAY,DaySequence - 1);//modification pour génerer les heures de la journée
//get the calendar date
var date = new java.util.Date(calendar.getTimeInMillis());
//en-us example: 9/3/07
var date_short = java.text.DateFormat.getDateInstance(
java.text.DateFormat.SHORT
, locale
).format(date);
//en-us example: Sep 3, 2007
var date_medium = java.text.DateFormat.getDateInstance(
java.text.DateFormat.MEDIUM
, locale
).format(date);
//en-us example: September 3, 2007
var date_long = java.text.DateFormat.getDateInstance(
java.text.DateFormat.LONG
, locale
).format(date);
//en-us example: Monday, September 3, 2007
var date_full = java.text.DateFormat.getDateInstance(
java.text.DateFormat.FULL
, locale
).format(date);
//day IN year: 1..366
var simpleDateFormat = java.text.SimpleDateFormat("D",locale);
var day_in_year = simpleDateFormat.format(date);
//day IN month: 1..31
simpleDateFormat.applyPattern("d");
var day_in_month = simpleDateFormat.format(date);
//en-us example: "Monday"
simpleDateFormat.applyPattern("EEEE");
var day_name = simpleDateFormat.format(date);
//en-us example: "Mon"
simpleDateFormat.applyPattern("E");
var day_abbreviation = simpleDateFormat.format(date);
//week IN year, 1..53
simpleDateFormat.applyPattern("ww");
var week_in_year = simpleDateFormat.format(date);
//week IN month, 1..5
simpleDateFormat.applyPattern("W");
var week_in_month = simpleDateFormat.format(date);
//month number IN year, 1..12
simpleDateFormat.applyPattern("MM");
var month_number = simpleDateFormat.format(date);
//en-us example: "September"
simpleDateFormat.applyPattern("MMMM");
var month_name = simpleDateFormat.format(date);
//en-us example: "Sep"
simpleDateFormat.applyPattern("MMM");
var month_abbreviation = simpleDateFormat.format(date);
//2 digit representation of the year, example: "07" FOR 2007
simpleDateFormat.applyPattern("y");
var year2 = simpleDateFormat.format(date);
//4 digit representation of the year, example: 2007
simpleDateFormat.applyPattern("yyyy");
var year4 = simpleDateFormat.format(date);
//handling Quarters IS a DIY
var quarter_name = "Q";
var quarter_number;
switch(parseInt(month_number)){
case 1: case 2: case 3: quarter_number = "1"; break;
case 4: case 5: case 6: quarter_number = "2"; break;
case 7: case 8: case 9: quarter_number = "3"; break;
case 10: case 11: case 12: quarter_number = "4"; break;
}
quarter_name += quarter_number;
//get the LOCAL yes/no VALUES
var yes = local_yes;
var no = local_no;
//initialize FOR week calculations
var first_day_of_week = calendar.getFirstDayOfWeek();
var day_of_week = java.util.Calendar.DAY_OF_WEEK;
//find out IF this IS the first day of the week
var is_first_day_in_week;
IF(first_day_of_week==calendar.get(day_of_week)){
is_first_day_in_week = yes;
} else {
is_first_day_in_week = no;
}
//calculate the next day
calendar.ADD(calendar.DAY_OF_MONTH,1);
//get the next calendar date
var next_day = new java.util.Date(calendar.getTimeInMillis());
//find out IF this IS the first day of the week
var is_last_day_in_week;
IF(first_day_of_week==calendar.get(day_of_week)){
is_last_day_in_week = yes;
} else {
is_last_day_in_week = no;
}
//find out IF this IS the first day of the month
var is_first_day_of_month;
IF(day_in_month == 1){
is_first_day_in_month = yes;
} else {
is_first_day_in_month = no;
}
//find out IF this IS the last day IN the month
var is_last_day_of_month;
IF(java.text.SimpleDateFormat("d",locale).format(next_day)==1){
is_last_day_in_month = yes;
} else {
is_last_day_in_month = no;
}
//date = year4 + "-" + month_number + "-" + day_in_month
var year_quarter = year4 + "-" + quarter_name;
var year_month_number = year4 + "-" + month_number;
var year_month_abbreviation = year4 + "-" + month_abbreviation;
IF ((day_name=='samedi' ) || (day_name=='dimanche') || (date_short=="01/11/09") || (date_short=="11/11/09") || (date_short=="25/12/09") || (date_short=="01/01/10") || (date_short=="05/04/10") || (date_short=="01/05/10") || (date_short=="08/05/10") || (date_short=="13/05/10") || (date_short=="24/05/10") || (date_short=="14/07/10") || (date_short=="15/08/10") || (date_short=="01/11/10") || (date_short=="11/11/10") || (date_short=="25/12/10")) {
var date_duration_hours= 0;
} else {
var date_duration_hours= 7;
} |
la transformation qui fait appel à ce script me permet de créer une dimension date tenant compte des heures de la journée, au date de passage à l'heure d'été je n'ai pas de ligne avec pour heure 02:00:00 ce qui est normal sauf que mon fichier de données brute qui va servir à remplir la table des faits à des lignes avec 02:00:00 même les jours il ne doit pas y en avoir...
kettle bloque sur ces lignes et me dit qu'il ne peut pas convertir la date de type string à l'origine (fichier csv) en type date...
j'aimerai bien pouvoir créer un calendrier comme plus haut mais sans tenir compte des changement d'heure et pouvoir convertir ma chaine de caractère ex : 30/03/1997 02:00:00 en date sans que java me génère d'erreur.
15/04/2011, 14h20
probleme heure d'été
00
